tlong jwb cpt
Penjelasan dengan langkah-langkah:
d1 = 21 cm
d2 = 10,5 cm
L arsir = L lingkaran besar - L lingkaran kecil
[tex] \frac{1}{4} \pi \: d1^{2} - \frac{1}{4} \pi \: d {2}^{2} = \frac{1}{4} \times \frac{22}{7} \times {21}^{2} - \frac{1}{4} \times \frac{22}{7} \times {10.5}^{2} \\ = \frac{1}{4} \times \frac{22}{7} \times 441 - \frac{1}{4} \times \frac{22}{7} \times 110.25 \\ = \frac{1}{4} \times 1386 - \frac{1}{4} \times 346.5 \\ = 346.5 - 86.625 = 259.875[/tex]
259,875cm²
Jawab:
[tex]697cm^{2}[/tex]
Penjelasan dengan langkah-langkah:
[tex](\pi[/tex] × [tex]r^{2})[/tex] - [tex](\pi[/tex] × [tex]\frac{1}{2}[/tex] × [tex]r^{2})[/tex]
= [tex](\frac{22}{7}[/tex] × [tex]21[/tex] × [tex]21)[/tex] - [tex](\frac{22}{7}[/tex] × [tex]\frac{1}{2}[/tex] × [tex]21[/tex] × [tex]21)[/tex]
= [tex](22[/tex] × [tex]3[/tex] × [tex]21)[/tex] - [tex](22[/tex] × [tex]\frac{1}{2}[/tex] × [tex]3[/tex] × [tex]21)[/tex]
= [tex](22[/tex] × [tex]3[/tex] × [tex]21)[/tex] - [tex](11[/tex] × [tex]3[/tex] × [tex]21)[/tex]
= [tex]1.386 - 689 = 697 cm^{2}[/tex]
